C++
#include <bits/stdc++.h>
using namespace std;
// Complete the alternatingCharacters function below.
int alternatingCharacters(string s) {
int c=0;
for(int i=0; i!=s.size(); i++){
if(s[i]==s[i+1]) c += 1;
}
return c;
}
int main()
{
ofstream fout(getenv("OUTPUT_PATH"));
int q;
cin >> q;
cin.ignore(numeric_limits<streamsize>::max(), '\n');
for (int q_itr = 0; q_itr < q; q_itr++) {
string s;
getline(cin, s);
int result = alternatingCharacters(s);
fout << result << "\n";
}
fout.close();
return 0;
}
- i번째와 i+1를 비교했을 때 같으면 제거하는 개수 카운팅을 증가한다.
- 이렇게 해서 최종으로 개수를 반환하면 된다.
Python
#!/bin/python3
import math
import os
import random
import re
import sys
# Complete the alternatingCharacters function below.
def alternatingCharacters(s):
count=0
for i in range(len(s)-1):
if s[i] == s[i+1]:
count += 1
return count
if __name__ == '__main__':
fptr = open(os.environ['OUTPUT_PATH'], 'w')
q = int(input())
for q_itr in range(q):
s = input()
result = alternatingCharacters(s)
fptr.write(str(result) + '\n')
fptr.close()